# Solutions of a Class of Deviated-Advanced Nonlocal Problems for the Differential Inclusion x 1 ( t ) ∈ F ( t , x ( t ) ) Academic research paper on "Mathematics" CC BY 0 0
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## Academic research paper on topic " Solutions of a Class of Deviated-Advanced Nonlocal Problems for the Differential Inclusion x 1 ( t ) ∈ F ( t , x ( t ) ) "

﻿Hindawi Publishing Corporation Abstract and Applied Analysis Volume 2011, Article ID 476392,9 pages doi:10.1155/2011/476392

Research Article

Solutions of a Class of Deviated-Advanced Nonlocal Problems for the Differential Inclusion

x1(t) e F(t,x(t))

A. M. A. El-Sayed,1 E. M. Hamdallah,1 and Kh. W. Elkadeky2

1 Faculty of Science, Alexandria University, Alexandria, Egypt

2 Faculty of Science, Garyounis University, Benghazi, Libya

Copyright © 2011 A. M. A. El-Sayed et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

We study the existence of solutions for deviated-advanced nonlocal and integral condition problems for the differential inclusion x1(t) e F{t,x(t)).

1. Introduction

Problems with nonlocal conditions have been extensively studied by several authors in the last two decades. The reader is referred to [1-12] and references therein. Consider the deviated-advanced nonlocal problem

dx(t) e F(t,x(t)), a.e. t e (0,1), (1.1)

^ükx(\$(Tk)) = aYjbjxiyiUj))' ak,bj > 0, (1.2)

k=1 j=1

where Tk,nj e (0,1), a > 0 is a parameter, and f and \$ are, respectively, deviated and advanced given functions.

Our aim here is to study the existence of at least one absolutely continuous solution x e AC[0,1] for the problem (1.1)-(1.2) when the set-valued function F : R ^ P(R) is L!-Caratheodory.

As an application, we deduce the existence of a solution for the nonlocal problem of the differential inclusion (1.1) with the deviated-advanced integral condition

x(\$(s))ds = a\ x(y(s))ds. (1.3)

It must be noticed that the following nonlocal and integral conditions are special cases of our nonlocal and integral conditions

x(<p(T^ = T,n e 1),

£akx(\$(Tk)) = ax(y(n)), Tk,n e (0,1), k=1

^akx(\$(Tk))= 0, Tk e (0,1),

I x(0(s))ds = ax(f(ц)), n e (a1), (14)

a\ x(y(s))ds = x(\$(t)), t e (0,1), Jo

f x(fi(s))ds = 0, J0

x(f (s)) ds

(s)) ds = 0.

As an example of the deviated function ty : (0,1) ^ (0,1), we have ty(t) = ¡t,fi e (0,1). As an example of the advanced function f : (0,1) ^ (0,1), we have f (t) = e (0,1).

2. Preliminaries

The following preliminaries are needed.

Definition 2.1. A set-valued function F : [0,1] x R ^ P(R) is called L!-Caratheodory if

(a) t ^ F(t,x) is measurable for each x e R,

(b) x ^ F(t, x) is upper semicontinuous for almost all t e [0,1],

(c) there exists m e L!([0,1],D), D c R such that

\F(t,x)\ = sup{\v\ : v e F(t,x)}< m(t), for almost all t e [0,1]. (2.1)

Definition 2.2. A single-valued function f : [0,1] x R ^ R is called L!-Caratheodory if (i) t ^ f (t,x) is measurable for each x e R,

(ii) x ^ f (t,x) is continuous for almost all t e [0,1],

(iii) there exists m e L1([0,1], D), D c R such that |f | < m. Definition 2.3. The set

skx(t)) = if e ([0,1],R) : f (t,x) e F(t,x(t)) fora.e. t e [0,1]} (2.2)

is called the set of selections of the set-valued function F.

Theorem 2.4. For any L1 -Caratheodory set-valued function F, the set SF(. x(t)) is nonempty [1,13]. Theorem 2.5 (Caratheodory, ). Let f : [0,1] x R ^ R be L1 -Caratheodory. Then the problem

= f (t,x(t)), fora.e. t > 0, x(0) = x0, (2.3)

has at least one solution x e AC[0, T].

3. Existence of Solution

Consider the following assumptions.

(i) F : [0,1] x R ^ P(R+) is L1-Caratheodory.

aTjbl = Yiak- (31)

j=1 k=1

(iii) \$ : (0,1) ^ (0,1),\$(t) < t is a deviated continuous function.

(iv) f : (0,1) ^ (0,1),f(t) > t is an advanced continuous function.

Now we have the following lemma.

Lemma 3.1. Let assumptions (i)-(ii) be satisfied. The solution of the nonlocal problem (1.1)-(1.2) can be expressed by the integral equation

f m f\$(rk) n ) \ At

x(t) = Al VaJ f(s,x(s))ds - f (s,x(s))ds \ + f(s,x(s))ds, (3.2)

\fc=1 j=1 Jq J JQ

where f (t, x) e F(t, x), for all x e R, and A = (a Xn=i bj - xm=i ak) 1

Proof. From the assumption that the set-valued function F : [0,1] x R ^ P(R+) is L1-Caratheodory, then (Theorem 2.4) there exists a single-valued selection f : [0,1] x R ^ R+ such that

dx(t) = f (t, x) e F(t, x), Vx e R. (3.3)

This selection f (t, x) is L1-Caratheodory. Integrating (3.3), we get

x(t) = x(0) + f f (s,x(s))ds. (3.4)

Let t = \$(Tk). Then

m mm f\$(Tk)

^akx^Tk ))=^ akx(0) + ^ ak f (s,x(s))ds. (3.5)

k=1 k=1 k=1 ^

Let t = ). Then

n n n )

a^bjxfyfy)) = a^bjx(0) + a^fy f (s,x(s))ds. (3.6)

j=i j=i j=i J°°

From (3.5) and (3.6), we obtain

f m f4>(rk) n ) \

x(0) = A YV f (s,x(s))ds - aYbj \ f (s,x(s))ds !, (3.7)

\k=1 Jo j=1 J0 J

n u vm \-1 ^ vn u -L

where A = (a j bj - ££1 ak)~1, aj bj = £™i ak. Substituting (3.7) into (3.4), we obtain

/ m f\$(Tk) n *tp(nj) \ *t

x(t) = A! VaJ f(s,x(s))ds - aYbj \ f (s,x(s))ds ! + f(s,x(s))ds. (3.8) \k=1 Jo j=i Jo J Jo

This proves that the solution of the nonlocal problem (1.1)-(1.2) can be expressed by the integral equation (3.2). □

For the existence of the solution, we have the following theorem.

Theorem 3.2. Assume that (i)-(iv) are satisfied. Then the integral equation (3.2) has at least one continuous solution x e C[0,1].

Proof. Define a subset Qr c C[0,1] by

Qr = \x e C[0,1] : \x(t) \ < r, r = AM f 1 + ^ak + a^bj^ 1. (3.9)

I \ k=1 J=1 /J

Clearly, the set Qr is nonempty, closed, and convex. Let H be an operator defined by

/ m f^(Tk) n *tp(m) \ At

(Hx)(t) = Al ^a^ f (s,x(s))ds - ^^b^ f(s,x(s))ds 1 + f (s,x(s))ds. \k=1 Jo j=1 Jo J Jo

(3.10)

Let x e Qr. Let {xn(t)} be a sequence in Qr converging to x(t), xn(t) ^ x(t), for all t e I. Then

f m r-\$(Tk) n *tp(m) \

lim (Hxn)(t) = A\ y,ak lim f (s,xn(s))ds - a^fo lim f (s,xn(s))ds j n^ no j=1 n^Jo )

k 1 j (3.11)

lim f (s, xn(s))ds,

" "'Jo

By assumptions (i)-(ii) and the Lebesgue dominated convergence theorem, we deduce that

lim (Hxn)(t) = (Hx)(t). (3.12)

Then H is continuous.

Now, letting x e Qr, (then \$(t) < t and f (t) > t), we obtain

f m t n Wj \

(Hx)(t) < A( ^ak\ f (s,x(s))ds - a^bj \ f (s,x(s))ds 1 \k=1 Jo j=1 Jo J

+ f (s,x(s))ds, Jo

f m t n a^j

\(Hx)(t)\< A[J\ak\ |f (s,x(s))\ds + aVfy \f(s,x(s))\ds \k=1 Jo j=1 Jo

+ |f (s,x(s)) |ds Jo

f m fTk n A^j \ At

< A! VaJ m(s)ds + ^Vb^ m(s)ds ! + ; \k=1 Jo j=1 Jo J Jo

/ m n \

< A( ^akM + a^bjM 1 + M

\fc=l ;=1 )

< AM! 1 + ^ak + a^bj ! < r.

\ k=1 H J

(3.13)

Then {Hx(t)} is uniformly bounded in Qr.

Also for ti,t2 e (0,i),ti < t2 such that |t2 - ti| < 6, we have

t2 ftl

ftl ftl (Hx)(t2) - (Hx)(t1) ^ f (s,x(s))ds - f (s,x(s))ds Jo Jo

l(Hx)(t2) - (Hx)(ti)l < f2\f(s,x(s)\ds

Jti (3.14)

< m(s)ds,

|(Hx)(t2) - (Hx)(ti)l< e.

Hence the class of functions {Hx(t)} is equicontinuous. By Arzela-Ascoli's theorem, {Hx(t)} is relatively compact. Since all conditions of Schauder's theorem hold, then H has a fixed point in Qr.

Therefore the integral equation (3.2) has at least one continuous solution x e C(0, i).

/ m rf(Tk) n *tp(m)

lim x(t) = A lim Xak f (s,x(s))ds - aY'.bi \ f(s,x(s))ds

t-0 t-o\k=1 Jo j=l Jo

+ lim f f (s,x(s))ds (3.15)

t - o V

/ m f\$(Tk) n *tp(nj) \

= A( Va^ f (s,x(s))ds - ^Vb^ f (s,x(s))ds ) = x(ü). \k=1 Jo j=1 Jo J

(3.16)

/ m f\$(rk) n )

x(i) = limx(t) = Al ^a^ f (s,x(s))ds - a^bj I f(s,x(s))ds

\k=i Jo j=i Jo

+ f(s,x(s))ds. Jo

Then the integral equation (3.2) has at least one continuous solution x e C[0, i]. □

The following theorem proves the existence of at least one solution for the nonlocal problem(1.1)-(1.2).

Theorem 3.3. Let (i)-(iv) be satisfied. Then the nonlocal problem (1.1)-(1.2) has at least one solution x e AC[0,1].

Proof. From Theorem 3.2 and the integral equation (3.2), we deduce that there exists at least one solution, x e AC[°,1], of the integral equation (3.2).

To complete the proof, we prove that the integral equation (3.2) satisfies nonlocal problem (1.1)-(1.2).

Differentiating (3.2), we get

— = f (t,x(t)) e F(t,x(t)), a.e. t e (0,1). (3.17)

Letting t = \$(Tfc) in (3.2), we obtain

m m / m \ ) m n )

^akx(\$(Tk)) = X aJA^ak + 1j f (s,x(s))ds - aA^a^bj f (s,x(s))ds.

k=1 k=1 \ k=1 / J0 k=1 j=1

(3.18)

Also, letting t = ) in (3.2), we obtain

n n m r^(Tk)

a^bjx(y(nj)) = aA^bj^akl f (s,x(s))ds

j=1 j=1 k=1

(3.19)

n / n \ )

■ a2_bj I 1 - aA2_bj I I f (s,x(s))ds.

j=1 \ j=1 J J°

And from (3.19) from (3.18), we obtain

£akx(\$(Tk ^ = a£bjx(v(m)).

(3.20)

This complete the proof of the equivalence between the nonlocal problem (1.1)-(1.2) and the integral equation (3.2).

This implies that there exists at least one absolutely continuous solution x e AC[°, 1] of the nonlocal problem (1.1)-(1.2). □

4. Nonlocal Integral Condition

Let x e [0,1] be a solution of the nonlocal problem (1.1)-(1.2). Let ak = tk - tk-1, Tk e (tk-1,tk) c (0,1). Also, let bj = tj - tj-1, n e (tj-1,tj) c (0,1). Then the nonlocal condition (1.2) will be

£(tk - tk-1)x(\$(Tk)) = a£(tj - tj-1)xtyj. (4.1)

k=1 j=1

From the continuity of the solution x of the nonlocal condition (1.2) we obtain

lim Y (tk - tk-1)x(\$(rk )) = lim aYÇtj - tj-1) x(f(m)). (4.2)

k=1 j=1

That is, the nonlocal condition (1.2) is transformed to the integral condition

x(\$(s))ds = a\ x(y(s))ds, (4.3)

and the solution of the integral equation (3.2) will be

/ f 1 f 1 (f(s)

x(t) = A*( f (d,x(d))ddds - a f (d,x(d))ddds

\Jo Jo Jo Jo

+ ( f (s,x(s))ds, A* = (a - 1)-1.

Now, we have the following theorem.

Theorem 4.1. Let assumptions (i)-(iv) of Theorem 3.2 be satisfied. Then the nonlocal problem with the integral condition

dx(t = f ( t,x(t)) e F( t, x( t)), for a.e. te (0,1),

x(\$(s)) ds = a x(y (s)) d

has at least one solution x e AC[0,1] represented by (4.4).

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